Find the logarithm of 0.125 to the base 2.

Let,

⇒ log₂ (0.125) = x

⇒ 0.125 = 2^x

⇒ $\dfrac{125}{1000} = 2^x$

⇒ $\dfrac{1}{8} = 2^x$

⇒ $\dfrac{1}{2^3} = 2^x$

⇒ 2^-3 = 2^x

⇒ x = -3.

Hence, required value = -3.