KnowledgeBoat Logo
|

Mathematics

Find the quotient and the remainder (if any), when:

a3 - 5a2 + 8a + 15 is divided by a + 1.

Algebraic Expressions

4 Likes

Answer

Dividing a3 - 5a2 + 8a + 15 by a + 1

a+1)a26a+14a+1)a35a2+8a+15a+1a3+a2a+12x6a2+8a+15a+121x+6a2+6aa+12x3++5x2+14a+15a+12x3++5x2+14a+14a+1a35a2+8a+1521\begin{array}{l} \phantom{a + 1)}{a^2 - 6a + 14} \ a + 1\overline{\smash{\big)}a^3 - 5a^2 + 8a + 15} \ \phantom{a + 1}\underline{\underset{-}{}a^3 \underset{-}{+}a^2} \ \phantom{{a + 1}2x}-6a^2 +8a + 15 \ \phantom{{a + 1}21x}\underline{\underset{+}{-}6a^2 \underset{+}{-} 6a} \ \phantom{{a + 1}{2x^3+}{+5x^2+}}14a + 15 \ \phantom{{a + 1}{2x^3+}{+5x^2}}\underline{\underset{+}{-}14a \underset{-}{+} 14} \ \phantom{{a + 1}{a^3 - 5a^2 + 8a + 152}} 1 \end{array}

Quotient = a2 - 6a + 14

Remainder = 1

Verification:

Quotient x Divisor + Remainder

= (a2 - 6a + 14) ×\times (a + 1) + 1

= a ×\times (a2 - 6a + 14) + 1 ×\times (a2 - 6a + 14) + 1

= a(1+2) - 6a(1+1) + 14a + a2 - 6a + 14 + 1

= a3 - 6a2 + 14a + a2 - 6a + 14 + 1

= a3 + (- 6a2 + a2) + (14a - 6a) + (14 + 1)

= a3 - 5a2 + 8a + 15

= Dividend

Answered By

1 Like


Related Questions