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Mathematics

Find the radius and area of a circle, whose circumference is :

(i) 132 cm

(ii) 22 m

Area Trapezium Polygon

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Answer

(i) Let r be the radius of the circle.

The circumference of a circle = 132 cm

As we know, the circumference of the circle = 2πr

2×227×r=132447×r=132r=132×744r=92444r=21 cm⇒ 2 \times \dfrac{22}{7} \times r = 132\\[1em] ⇒ \dfrac{44}{7} \times r = 132\\[1em] ⇒ r = \dfrac{132 \times 7}{44}\\[1em] ⇒ r = \dfrac{924}{44}\\[1em] ⇒ r = 21 \text{ cm}

And, area of the circle = πr2

=227×212=227×441=9,7027=1,386 cm2= \dfrac{22}{7} \times 21^2\\[1em] = \dfrac{22}{7} \times 441\\[1em] = \dfrac{9,702}{7}\\[1em] = 1,386 \text{ cm}^2

Hence, the radius of the circle is 21 cm and the area is 1,386 cm2.

(ii) Let r be the radius of the circle.

The circumference of a circle = 22 cm

As we know, the circumference of the circle = 2πr

2×227×r=22447×r=22r=22×744r=15444r=3.5 m⇒ 2 \times \dfrac{22}{7} \times r = 22\\[1em] ⇒ \dfrac{44}{7} \times r = 22\\[1em] ⇒ r = \dfrac{22 \times 7}{44}\\[1em] ⇒ r = \dfrac{154}{44}\\[1em] ⇒ r = 3.5 \text{ m}

And, area of the circle = πr2

=227×3.52=227×12.25=269.507=38.5 m2= \dfrac{22}{7} \times 3.5^2\\[1em] = \dfrac{22}{7} \times 12.25\\[1em] = \dfrac{269.50}{7}\\[1em] = 38.5 \text{ m}^2

Hence, the radius of the circle is 3.5 m and the area is 38.5 m2.

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