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Mathematics

Find the radius and circumference of a circle, whose area is :

(i) 154 cm2

(ii) 6.16 m2

Area Trapezium Polygon

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Answer

(i) Let r be the radius of the circle.

The area of circle = 154 cm2

As we know, the area of the circle = πr2

227×r2=154r2=154×722r2=1,07822r2=49r=49r=7 cm⇒ \dfrac{22}{7} \times r^2 = 154\\[1em] ⇒ r^2 = \dfrac{154 \times 7}{22}\\[1em] ⇒ r^2 = \dfrac{1,078}{22}\\[1em] ⇒ r^2 = 49\\[1em] ⇒ r = \sqrt{49}\\[1em] ⇒ r = 7 \text{ cm}

Circumference of the circle = 2πr

=2×227×7=447×7=3087=44 cm= 2 \times \dfrac{22}{7} \times 7\\[1em] = \dfrac{44}{7} \times 7\\[1em] = \dfrac{308}{7}\\[1em] = 44 \text{ cm}

Hence, the radius of the circle is 7 cm and the circumference is 44 cm.

(ii) Let r be the radius of the circle.

The area of circle = 6.16 m2

As we know, the area of the circle = πr2

227×r2=6.16r2=6.16×722r2=43.1222r2=1.96r=1.96r=1.4 m⇒ \dfrac{22}{7} \times r^2 = 6.16\\[1em] ⇒ r^2 = \dfrac{6.16 \times 7}{22}\\[1em] ⇒ r^2 = \dfrac{43.12}{22}\\[1em] ⇒ r^2 = 1.96\\[1em] ⇒ r = \sqrt{1.96}\\[1em] ⇒ r = 1.4 \text{ m}

Circumference of the circle = 2πr

=2×227×1.4=447×1.4=61.67=8.8 m= 2 \times \dfrac{22}{7} \times 1.4\\[1em] = \dfrac{44}{7} \times 1.4\\[1em] = \dfrac{61.6}{7}\\[1em] = 8.8 \text{ m}

Hence, the radius of the circle is 1.4 m and the circumference is 8.8 m.

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