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Mathematics

Find the roots of the following quadratic equation by factorisation :

2x2+7x+52=0\sqrt{2}x^2 +7x + 5\sqrt{2} = 0

Quadratic Equations

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Answer

Solving,

2x2+7x+52=02x2+2x+5x+52=02x(x+2)+5(x+2)=0(2x+5)(x+2)=02x+5=0 or x+2=02x=5 or x=2x=52 or x=2.\Rightarrow \sqrt{2}x^2 + 7x + 5\sqrt{2} = 0 \\[1em] \Rightarrow \sqrt{2}x^2 + 2x + 5x + 5\sqrt{2} = 0 \\[1em] \Rightarrow \sqrt{2}x(x + \sqrt{2}) + 5(x + \sqrt{2}) = 0 \\[1em] \Rightarrow (\sqrt{2}x + 5)(x + \sqrt{2}) = 0 \\[1em] \Rightarrow \sqrt{2}x + 5 = 0 \text{ or } x + \sqrt{2} = 0 \\[1em] \Rightarrow \sqrt{2}x = -5 \text{ or } x = -\sqrt{2} \\[1em] \Rightarrow x = -\dfrac{5}{\sqrt{2}} \text{ or } x = -\sqrt{2}.

Hence, x = 52 or x=2-\dfrac{5}{\sqrt{2}}\text{ or x} = -\sqrt{2}.

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