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Mathematics

Find the sub-triplicate ratio of :

(i) 1 : 216

(ii) 18:1125\dfrac{1}{8} : \dfrac{1}{125}

(iii) 27a3 : 64b3

Ratio Proportion

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Answer

(i) The sub-triplicate ratio of 1 : 216 is,

=13:2163=1:6= \sqrt[3]{1} : \sqrt[3]{216} \\[0.5em] = 1 : 6

Hence, the sub-triplicate ratio is 1 : 6.

(ii) The sub-triplicate ratio of 18:1125\dfrac{1}{8} : \dfrac{1}{125} is,

=183:11253=12:15=1215=52=5:2= \sqrt[3]{\dfrac{1}{8}} : \sqrt[3]{\dfrac{1}{125}} \\[0.5em] = \dfrac{1}{2} : \dfrac{1}{5} \\[0.5em] = \dfrac{\dfrac{1}{2}}{\dfrac{1}{5}} \\[0.5em] = \dfrac{5}{2} = 5 : 2

Hence, the sub-triplicate ratio is 5 : 2.

(iii) The sub-triplicate ratio of 27a3 : 64b3 is,

=27a33:64b33=3a:4b= \sqrt[3]{27a^3} : \sqrt[3]{64b^3} \\[0.5em] = 3a : 4b

Hence, the sub-triplicate ratio is 3a : 4b.

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