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Mathematics

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.

t2 - 15

Polynomials

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Answer

Let,

⇒ t2 - 15 = 0

(t15)(t+15)=0(t - \sqrt{15})(t + \sqrt{15}) = 0

(t15) or (t+15)=0(t - \sqrt{15}) \text{ or } (t + \sqrt{15}) = 0

t=15 or 15t = \sqrt{15} \text{ or } -\sqrt{15}

Sum of zeroes = 15+(15)=0=(Coefficient of t)(Coefficient of t2)\sqrt{15} + (-\sqrt{15}) = 0 = \dfrac{-\text{(Coefficient of t)}}{\text{(Coefficient of t}^2)}

Product of zeroes = 15×15=15=Constant termCoefficient of t2-\sqrt{15} \times \sqrt{15} = -15 = \dfrac{\text{Constant term}}{\text{Coefficient of t}^2}

Hence, for zero of the polynomial t2 - 15, t = 15,15-\sqrt{15}, \sqrt{15}.

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