Mathematics

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
4u² + 8u

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Let,

⇒ 4u² + 8u = 0

⇒ 4u(u + 2) = 0

⇒ 4u = 0 or u + 2 = 0

⇒ u = 0 or u = -2.

Sum of zeroes = 0 + (-2) = -2 = $\dfrac{-8}{4} = \dfrac{-\text{(Coefficient of u)}}{\text{(Coefficient of u}^2)}$

Product of zeroes = 0 × (-2) = 0 = $\dfrac{\text{Constant term}}{\text{Coefficient of x}^2}$

Hence, for zero of the polynomial 4u² + 8u, u = 0, -2.

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