Find two numbers such that the sum of thrice the first and the second is 142 and four times the first exceeds the second by 138.
Linear Equations
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Question

Find two numbers such that the sum of thrice the first and the second is 142 and four times the first exceeds the second by 138.

KnowledgeBoat · Accepted Answer

Let two numbers be x and y. Given, Sum of thrice the first and the second = 142 ⇒ 3x + y = 142 ⇒ y = 142 - 3x .....(1) Given, Four times the first exceeds the second by 138. ⇒ 4x - y = 138 ⇒ 4x = y + 138 ......(2) Substituting value of y from equation (1) in (2), we get : ⇒ 4x = 142 - 3x + 138 ⇒ 4x + 3x = 142 + 138 ⇒ 7x = 280 ⇒ x = . Substituting value of x in equation (1), we get : ⇒ y = 142 - 3x ⇒ y = 142 - 3(40) ⇒ y = 142 - 120 ⇒ y = 22. Hence, the numbers are 40 and 22.

Mathematics

Find two numbers such that the sum of thrice the first and the second is 142 and four times the first exceeds the second by 138.

Linear Equations

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