Mathematics
Find two numbers such that the sum of thrice the first and the second is 142 and four times the first exceeds the second by 138.
Linear Equations
2 Likes
Answer
Let two numbers be x and y.
Given,
Sum of thrice the first and the second = 142
⇒ 3x + y = 142
⇒ y = 142 - 3x …..(1)
Given,
Four times the first exceeds the second by 138.
⇒ 4x - y = 138
⇒ 4x = y + 138 ……(2)
Substituting value of y from equation (1) in (2), we get :
⇒ 4x = 142 - 3x + 138
⇒ 4x + 3x = 142 + 138
⇒ 7x = 280
⇒ x = .
Substituting value of x in equation (1), we get :
⇒ y = 142 - 3x
⇒ y = 142 - 3(40)
⇒ y = 142 - 120
⇒ y = 22.
Hence, the numbers are 40 and 22.
Answered By
2 Likes
Related Questions
The sum of two numbers is 51. If the larger is doubled and the smaller is tripled, the difference is 12. Find the numbers.
Find two numbers such that the sum of twice the first and thrice the second is 103 and four times the first exceeds seven times the second by 11.
Of the two numbers, 4 times the smaller one is less than 3 times the larger one by 6. Also, the sum of the numbers is larger than 6 times their difference by 5. Find the numbers.
If from twice the greater number of the two numbers, 45 is subtracted, the result is the other number. If from twice the smaller number, 21 is subtracted, the result is the greater number. Find the numbers.