Find two numbers whose mean proportion is 36 and the third proportional is 288.

Question

KnowledgeBoat · Accepted Answer

Let the two numbers be x and y. Thus, 36 is the mean proportion between x and y. The third proportional for x and y is 288. Substituting value of x from equation (1) in (2), we get : Substituting the value of y in equation (1), we get : Hence, the two numbers are 18 and 72.

Mathematics

Find two numbers whose mean proportion is 36 and the third proportional is 288.

Ratio Proportion

Related Questions

The following numbers, K + 3, K + 2, 3K − 7 and 2K − 3 are in proportion. Find the value of K.

If (x + 5) is the geometric mean between (x + 2) and (x + 9), find the value of x.

If a : b :: c : d, prove that :
(i) (a² + ab) : (c² + cd) = (b² − 2ab) : (d² − 2cd)
(ii) (a² + b²) : (c² + d²) = (ab + ad − bc) : (cd − ad + bc)
(iii) (a² + ac + c²) : (a² − ac + c²) = (b² + bd + d²) : (b² − bd + d²)

Mathematics

Find two numbers whose mean proportion is 36 and the third proportional is 288.

Ratio Proportion

Related Questions

The following numbers, K + 3, K + 2, 3K − 7 and 2K − 3 are in proportion. Find the value of K.

If (x + 5) is the geometric mean between (x + 2) and (x + 9), find the value of x.

If a : b :: c : d, prove that :(i) (a2 + ab) : (c2 + cd) = (b2 − 2ab) : (d2 − 2cd)(ii) (a2 + b2) : (c2 + d2) = (ab + ad − bc) : (cd − ad + bc)(iii) (a2 + ac + c2) : (a2 − ac + c2) = (b2 + bd + d2) : (b2 − bd + d2)

If a : b :: c : d, prove that :
(i) (a² + ab) : (c² + cd) = (b² − 2ab) : (d² − 2cd)
(ii) (a² + b²) : (c² + d²) = (ab + ad − bc) : (cd − ad + bc)
(iii) (a² + ac + c²) : (a² − ac + c²) = (b² + bd + d²) : (b² − bd + d²)