If =[(-3,2)(0,-5)][(x)(2)] , find the values of x and y.

Given, = Solving: ∴ y = -10 ∴ -3x + 4 = -5 ⇒ -3x = -5 - 4 ⇒ -3x = -9 ⇒ x = ⇒ x = 3. Hence, x = 3 and y = -10.

Mathematics

If $\begin{bmatrix} -3 & 2 \ 0 & -5 \end{bmatrix}$ $\begin{bmatrix} x \ 2 \end{bmatrix}$ = $\begin{bmatrix} -5 \ y \end{bmatrix}$ , find the values of x and y.

Matrices

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Answer

Given,

$\begin{bmatrix} -3 & 2 \ 0 & -5 \end{bmatrix}$ $\begin{bmatrix} x \ 2 \end{bmatrix}$ = $\begin{bmatrix} -5 \ y \end{bmatrix}$

Solving:

$\Rightarrow \begin{bmatrix} (-3)(x) + (2)(2) \ (0)(x) + (-5)(2) \end{bmatrix} = \begin{bmatrix} -5 \ y \end{bmatrix} \\[1em] \Rightarrow \begin{bmatrix} -3x + 4 \ -10 \end{bmatrix} = \begin{bmatrix} -5 \ y \end{bmatrix}.$

∴ y = -10

∴ -3x + 4 = -5

⇒ -3x = -5 - 4

⇒ -3x = -9

⇒ x = $\dfrac{-9}{-3}$

⇒ x = 3.

Hence, x = 3 and y = -10.

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Mathematics

If $\begin{bmatrix} -3 & 2 \ 0 & -5 \end{bmatrix}$ $\begin{bmatrix} x \ 2 \end{bmatrix}$ = $\begin{bmatrix} -5 \ y \end{bmatrix}$ , find the values of x and y.

Matrices

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