Find 'x', if :
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sin 60°=PerpendicularHypotenuse⇒32=20x⇒x=20×23⇒x=403⇒x=23.1\text{sin 60°} = \dfrac{Perpendicular}{Hypotenuse}\\[1em] ⇒ \dfrac{\sqrt3}{2} = \dfrac{20}{x}\\[1em] ⇒ x = \dfrac{20 \times 2}{\sqrt3}\\[1em] ⇒ x = \dfrac{40}{\sqrt3} \\[1em] ⇒ x = 23.1sin 60°=HypotenusePerpendicular⇒23=x20⇒x=320×2⇒x=340⇒x=23.1
Hence, x = 23.1.
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From the information given in the triangle shown below, the length of CD is :
(take 3{\sqrt3}3 = 1.732)
(i) 7.32 m
(ii) 27.32 m
(iii) 10 m
(iv) 17.32 m
In the given triangle, the length of AB is :
160 cm
120 cm
60 cm
40 cm
