Find 'x', if :
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sin 45°=PerpendicularHypotenuse⇒12=20x⇒x=20×2⇒x=28.28\text{sin 45°} = \dfrac{Perpendicular}{Hypotenuse}\\[1em] ⇒ \dfrac{1}{\sqrt2} = \dfrac{20}{x}\\[1em] ⇒ x = 20 \times \sqrt2\\[1em] ⇒ x = 28.28sin 45°=HypotenusePerpendicular⇒21=x20⇒x=20×2⇒x=28.28
Hence, x = 28.28.
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Find angle 'A' if :