Five years ago, Mohit was thrice of Manish. 10 years later, Mohit will be twice as old an Manish. Find their present ages.

Question

KnowledgeBoat · Accepted Answer

Let the age of Manish be x. According to the question, five years ago, Mohit was three times as old as Manish. ⇒ Mohit's age \- 5 years = 3 x (Manish's age \- 5 years) ⇒ Mohit's age \- 5 = 3(x \- 5) ⇒ Mohit's age \- 5 = 3x \- 15 ⇒ Mohit's age = 3x \- 15 \+ 5 ⇒ Mohit's age = 3x \- 10 ...............(1) And, Ten years later, Mohit will be twice as old as Manish. ⇒ Mohit's age \+ 10 years = 2 x (Manish's age \+ 10 years) ⇒ Mohit's age \+ 10 = 2(x \+ 10) ⇒ Mohit's age \+ 10 = 2x \+ 20 ⇒ Mohit's age = 2x \+ 20 \- 10 ⇒ Mohit's age = 2x \+ 10 From equation (1), ⇒ 3x \- 10 = 2x \+ 10 ⇒ 3x \- 2x = 10 \+ 10 ⇒ x = 20 Mohit's age = 3x \- 10 = 3 20 \- 10 = 60 \- 10 = 50 Hence, the present age of Mohit is 50 years, and the present age of Manish is 20 years.

Mathematics

Five years ago, Mohit's age was thrice of Manish. 10 years later, Mohit will be twice as old as Manish. Find their present ages.

Linear Eqns One Variable

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