It is found, on heating a gas, its volume increases by 50% and pressure increased by 60% of its original value. If the original temperature was -15°C, find the temperature to which it was heated?
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It is found, on heating a gas, its volume increases by 50% and pressure increased by 60% of its original value. If the original temperature was -15°C, find the temperature to which it was heated?

KnowledgeBoat · Accepted Answer

Initial conditions [S.T.P.] : P1 = Initial pressure of the gas = P V1 = Initial volume of the gas = V T1 = Initial temperature of the gas = -15°C = -15 + 273 = 258 K Final conditions : P2 (Final pressure) = pressure increases by 60% of its original value = 1 + of P = of P = of P = P V2 (Final volume) = volume increases by 50% of its original value = 1 + of V = of V = of V = V T2 (Final temperature) = ? By Gas Law: Substituting the values : ∴ Final temperature of the gas = 619.2 - 273 = 346.2°C

Chemistry

It is found, on heating a gas, its volume increases by 50% and pressure increased by 60% of its original value. If the original temperature was -15°C, find the temperature to which it was heated?

Gas Laws

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It is found, on heating a gas, its volume increases by 50% and pressure increased by 60% of its original value. If the original temperature was -15°C, find the temperature to which it was heated?

Gas Laws

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