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Mathematics

The fourth term of a Geometric Progression (G.P.) is 16 and its seventh term is 128. Find its:

(a) common ratio

(b) first term

G.P.

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Answer

(a) We know that,

an = arn - 1

Given,

a4 = ar3 = 16 ….(1)

a7 = ar6 = 128 …..(2)

Dividing equation (2) by equation (1), we get :

ar6ar3=12816r3=8r=83=2.\Rightarrow \dfrac{ar^6}{ar^3} = \dfrac{128}{16} \\[1em] \Rightarrow r^3 = 8 \\[1em] \Rightarrow r = \sqrt[3]{8} = 2.

Hence, common ratio = 2.

(b) The first term,

Substituting r = 2 in equation (1), we get :

⇒ a(2)3 = 16

⇒ a(8) = 16

⇒ a = 168\dfrac{16}{8}

⇒ a = 2.

Hence, first term = 2.

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