Given 3(log 5 - log 3) - (log 5 - 2log 6) = 2 - log n, find n.

Question

KnowledgeBoat · Accepted Answer

Given, 3(log 5 - log 3) - (log 5 - 2log 6) = 2 - log n ⇒ 3log 5 - 3log 3 - log 5 + 2log 6 = 2 - log n ⇒ 2log 5 - log 3³ + log 6² = 2 - log n ⇒ log 5² - log 27 + log 36 = 2 - log n ⇒ log 25 - log 27 + log 36 = 2log 10 - log n ⇒ log = log 10² - log n ⇒ log = log 100 - log n ⇒ log 100 - log 3 = log 100 - log n ⇒ log n = log 3 ⇒ n = 3. Hence, n = 3.

Mathematics

Given 3(log 5 - log 3) - (log 5 - 2log 6) = 2 - log n, find n.

Logarithms

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Mathematics

Given 3(log 5 - log 3) - (log 5 - 2log 6) = 2 - log n, find n.

Logarithms

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