Mathematics
In the given diagram ∆ADB and ∆ACB are two right angled triangles with ∠ADB = ∠BCA = 90°. If AB = 10 cm, AD = 6 cm, BC = 2.4 cm and DP = 4.5 cm
(a) Prove that ∆APD ∼ ∆BPC.
(b) Find the length of BD and PB
(c) Hence, find the length of PA
(d) Find area ∆APD : area ∆BPC
Related Questions
Solve the following quadratic equation for x and give your answer correct to three significant figures :
2x2 - 10x + 5 = 0
The nth term of an Arithmetic Progression (A.P.) is given by the relation Tn = 6(7 - n). Find ∶
(a) its first term and common difference
(b) sum of its first 25 terms
In the given diagram, an isosceles ∆ABC is inscribed in a circle with centre O. PQ is a tangent to the circle at C. OM is perpendicular to chord AC and ∠COM = 65°. Find :
(a) ∠ABC
(b) ∠BAC
(c) ∠BCQ
