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In the given diagram, the radius of the circle with centre O is 3 cm. PA and PB are the tangents to the circle which are at right angle to each other. The length of OP is:

In the given diagram, the radius of the circle with centre O is 3 cm. PA and PB are the tangents to the circle which are at right angle to each other. The length of OP is: ICSE 2026 Maths Solved Question Paper.
  1. 32\dfrac{3}{\sqrt{2}} cm

  2. 3 cm

  3. 323\sqrt{2} cm

  4. 626\sqrt{2} cm

Circles

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Answer

Join OA and AP.

In the given diagram, the radius of the circle with centre O is 3 cm. PA and PB are the tangents to the circle which are at right angle to each other. The length of OP is: ICSE 2026 Maths Solved Question Paper.

Given,

Radius of circle (OB) = 3 cm

PB and AP are at right angles.

We know that,

Radius and tangent at point of contact are perpendicular to each other.

OA ⊥ AP

From figure,

⇒ OA = OB = 3 cm [Radius of circle]

⇒ OB is perpendicular to PB

⇒ ∠OBP = 90°

This shows APBO is square.

OA = PB = AP = OB = 3 cm.

In right angled triangle OBP,

⇒ OP2 = OB2 + PB2

⇒ OP2 = 32 + 32

⇒ OP2 = 9 + 9

⇒ OP2 = 18

⇒ OP = 18\sqrt{18}

⇒ OP = 323\sqrt{2} cm.

Hence, option 3 is the correct option.

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