Mathematics
Answer
From figure,
∠ECF = 90°, ∠CEF = 30°, ∠AFD = 80°
In △ECF, the sum of interior angles is 180°.
∴ ∠ECF + ∠CEF + ∠EFC = 180°
⇒ 90° + 30° + x° = 180°
⇒ 120° + x° = 180°
⇒ x° = 180° - 120°
⇒ x° = 60°
Consider, AB || CD:
z° and 80° are co-interior angles.
Co-interior angles are supplementary:
∴ z° + 80° = 180°
⇒ z° = 180° - 80°
⇒ z° = 100°
Since CD is a straight line, the sum of all angles on one side of a straight line at a point is 180°.
∴ x° + y° + 80° = 180°
⇒ 60° + y° + 80° = 180°
⇒ y° + 140° = 180°
⇒ y° = 180° - 140°
⇒ y° = 40°
x° = 60°, y° = 40° and z° = 100°
Related Questions
In the given figure, l || m || n and p || q || r. Find the angles x, y, z and t.

In the given figure, l || m and p || q. Find the angles x, y, z and t.

In the given figure, l || m and p || q. Find the angles x, y and z.

In each of the following figures, two lines AB and CD are cut by a transversal EF. In each case, find whether AB || CD or not. Give reasons in support of your answer.
(i)

(ii)

(iii)

(iv)

(v)

