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In the given figure, ∠ABC = 90° and BD ⟂ AC. If AB = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm, find BC.

In the given figure, ∠ABC = 90° and BD ⟂ AC. If AB = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm, find BC. Similarity of Triangles, RSA Mathematics Solutions ICSE Class 10.

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Answer

We have, ∠ABC = 90° and BD ⟂ AC

In ΔABC and ΔBDC,

∠ABC = ∠BDC [Each 90°]

∠ACB = ∠BCD [Common]

∴ ΔABC ∼ ΔBDC (By A.A. axiom)

We know that,

Corresponding sides of similar triangles are proportional.

ABBD=BCDC5.73.8=BC5.4BC=5.7×5.43.8BC=30.783.8BC=8.1 cm.\therefore \dfrac{AB}{BD} = \dfrac{BC}{DC} \\[1em] \Rightarrow \dfrac{5.7}{3.8} = \dfrac{BC}{5.4} \\[1em] \Rightarrow BC = \dfrac{5.7 \times 5.4}{3.8}\\[1em] \Rightarrow BC = \dfrac{30.78}{3.8}\\[1em] \Rightarrow BC = 8.1 \text{ cm}.

Hence, BC = 8.1 cm.

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