In the given figure, ABCD is a trapezium in which AB || CD. If area of △BEC is 12 cm2, then area of △EDC is : 2, then area of △EDC is. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9." 1. 12 cm2 2. 6 cm2 3. 24 cm2 4. none of these

Question

In the given figure, ABCD is a trapezium in which AB || CD. If area of △BEC is 12 cm2, then area of △EDC is : 2, then area of △EDC is. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9." > 1. 12 cm2 2. 6 cm2 3. 24 cm2 4. none of these

KnowledgeBoat · Accepted Answer

Since, AB || DC. ∴ Triangles BEC and EDC lie between the same parallel lines. Both triangles have the same height (distance between AB and CD). There bases are also equal: Base of △BEC = EB = 6 cm Base of △EDC = DC = 6 cm We know that, Area of triangle = × base × height Since both triangles (△BEC and △EDC) have same height and base. So, there areas are also equal. ∴ Area of △BEC = Area of △EDC = 12 cm2. Hence, option 1 is the correct option.

Mathematics

In the given figure, ABCD is a trapezium in which AB || CD. If area of △BEC is 12 cm², then area of △EDC is :
12 cm²
6 cm²
24 cm²
none of these

Mensuration

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