Mathematics

In the given figure, ∠PQR = ∠PST = 90°, PQ = 5 cm and PS = 2 cm.

(i) Prove that ΔPQR ∼ ΔPST.

(ii) Find area of ΔPQR : Area of quadrilateral SRQT.

In the given figure, ∠PQR = ∠PST = 90°, PQ = 5 cm and PS = 2 cm. Similarity of Triangles, RSA Mathematics Solutions ICSE Class 10.

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