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Mathematics

Given log10a = b, express 102b - 3 in terms of a.

Logarithms

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Answer

Given,

⇒ log10a = b

∴ a = 10b.

Simplifying 102b - 3 we get,

⇒ 102b - 3 = 102b.10-3

= 102b103=(10b)2103\dfrac{10^{2b}}{10^3} = \dfrac{(10^b)^2}{10^3}

= a2103=a21000\dfrac{a^2}{10^3} = \dfrac{a^2}{1000}.

Hence, 102b - 3 = a21000.\dfrac{a^2}{1000}.

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