Solve the following equation for x: log x = -2, 0, 1/3.

Given, ⇒ log x = -2 ⇒ x = 10 -2 = . ⇒ log x = 0 ⇒ x = 10 0 = 1. ⇒ log x = ⇒ x = Hence, x =

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Mathematics

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Given,

⇒ log x = -2

⇒ x = 10^-2 = $\dfrac{1}{10^2} = \dfrac{1}{100}$ .

⇒ log x = 0

⇒ x = 10⁰ = 1.

⇒ log x = $\dfrac{1}{3}$

⇒ x = $10^{\dfrac{1}{3}} = \sqrt[3]{10}.$

Hence, x = $\dfrac{1}{100}, 1, \sqrt[3]{10}.$

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