If 4^{x + 3} = 112 + 8 × 4^x; find (18x)^3x.

Question

KnowledgeBoat · Accepted Answer

Given, ⇒ 4^{x + 3} = 112 + 8 × 4^x ⇒ 4^x.4³ = 8(14 + 4^x) ⇒ 64.4^x = 8(14 + 4^x) ⇒ = 14 + 4^x ⇒ 8.4^x = 14 + 4^x ⇒ 8.4^x - 4^x = 14 ⇒ 4^x(8 - 1) = 14 ⇒ 7.4^x = 14 ⇒ 4^x = ⇒ (2²)^x = 2 ⇒ 2^2x = 2¹ ⇒ 2x = 1 ⇒ x = . Substituting value of x in (18x)^3x, we get : Hence, (18x)^3x = 27.

Mathematics

If 4^{x + 3} = 112 + 8 × 4^x; find (18x)^3x.

Indices

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Mathematics

If 4x + 3 = 112 + 8 × 4x; find (18x)3x.

Indices

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If 4^{x + 3} = 112 + 8 × 4^x; find (18x)^3x.

If m ≠ n and (m + n)^-1 (m^-1 + n^-1) = m^xn^y;
show that : x + y + 2 = 0

If 5^{x + 1} = 25^{x - 2}; find the value of :
3^{x - 3} × 2^{3 - x}.

Solve for x :
(a^{3x + 5})².(a^x)⁴ = a^{8x + 12}