If a = tan θ and b = sec θ, the relation between a and b is : 1. a × b = 1 2. a 2 - b 2 = 1 3. b 2 - a 2 = 1 4. a 2 + b 2 = 1

Substituting value of a and b in L.H.S. of option 3, we get : ⇒ b 2 - a 2 ⇒ sec 2 A - tan 2 A ⇒ 1. Since, L.H.S. = R.H.S. Hence, Option 3 is the correct option.

Mathematics

If a = tan θ and b = sec θ, the relation between a and b is :
a × b = 1
a² - b² = 1
b² - a² = 1
a² + b² = 1

Trigonometric Identities

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Answer

Substituting value of a and b in L.H.S. of option 3, we get :

⇒ b² - a²

⇒ sec² A - tan² A

⇒ 1.

Since, L.H.S. = R.H.S.

Hence, Option 3 is the correct option.

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Mathematics

If a = tan θ and b = sec θ, the relation between a and b is :
a × b = 1
a² - b² = 1
b² - a² = 1
a² + b² = 1

Trigonometric Identities

Answer

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(sec θ - cos θ)² - (sec θ + cos θ)² is equal to :
4
2
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Mathematics

If a = tan θ and b = sec θ, the relation between a and b is :a × b = 1a2 - b2 = 1b2 - a2 = 1a2 + b2 = 1

Trigonometric Identities

Answer

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(sec θ - cos θ)2 - (sec θ + cos θ)2 is equal to :42-2-4

If a = tan θ and b = sec θ, the relation between a and b is :
a × b = 1
a² - b² = 1
b² - a² = 1
a² + b² = 1

(sec θ - cos θ)² - (sec θ + cos θ)² is equal to :
4
2
-2
-4