Mathematics
(sec θ - cos θ)2 - (sec θ + cos θ)2 is equal to :
4
2
-2
-4
Trigonometric Identities
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Answer
Solving,
⇒ (sec θ - cos θ)2 - (sec θ + cos θ)2
⇒ (sec θ - cos θ + sec θ + cos θ)[(sec θ - cos θ) - (sec θ + cos θ)] [∵ a2 - b2 = (a + b)(a - b)]
⇒ (sec θ - cos θ + sec θ + cos θ)(sec θ - sec θ - cos θ - cos θ)
⇒ 2 sec θ.(-2 cos θ)
⇒ -4.sec θ.cos θ
⇒
⇒ -4.
Hence, Option 4 is the correct option.
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Related Questions
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b2 - a2 = 1
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Prove that:
(sec A - tan A)2 (1 + sin A) = (1 - sin A)