If a 2 + b 2 + c 2 = 50 and ab + bc + ca = 47, find a + b + c.

By formula, (a + b + c) 2 = a 2 + b 2 + c 2 + 2(ab + bc + ca). Substituting values we get : ⇒ (a + b + c) 2 = 50 + 2 × 47 ⇒ (a + b + c) 2 = 50 + 94 ⇒ (a + b + c) 2 = 144 ⇒ (a + b + c) = . Hence, (a + b + c) = .

If a² + b² + c² = 35 and ab + bc + ca = 23; find a + b + c.

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If a + b + c = p and ab + bc + ca = q; find a² + b² + c².

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If x + y - z = 4 and x² + y² + z² = 30, then find the value of xy - yz - zx.

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The longest road that can be placed in a rectangular box = 20 cm and the sum of its length breadth and height is 30 cm. Find the total surface area of the box.

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Mathematics

If a² + b² + c² = 50 and ab + bc + ca = 47, find a + b + c.

Expansions

Related Questions

If a² + b² + c² = 35 and ab + bc + ca = 23; find a + b + c.

If a + b + c = p and ab + bc + ca = q; find a² + b² + c².

If x + y - z = 4 and x² + y² + z² = 30, then find the value of xy - yz - zx.

The longest road that can be placed in a rectangular box = 20 cm and the sum of its length breadth and height is 30 cm. Find the total surface area of the box.

Mathematics

If a2 + b2 + c2 = 50 and ab + bc + ca = 47, find a + b + c.

Expansions

Related Questions

If a2 + b2 + c2 = 35 and ab + bc + ca = 23; find a + b + c.

If a + b + c = p and ab + bc + ca = q; find a2 + b2 + c2.

If x + y - z = 4 and x2 + y2 + z2 = 30, then find the value of xy - yz - zx.

The longest road that can be placed in a rectangular box = 20 cm and the sum of its length breadth and height is 30 cm. Find the total surface area of the box.

If a² + b² + c² = 50 and ab + bc + ca = 47, find a + b + c.

If a² + b² + c² = 35 and ab + bc + ca = 23; find a + b + c.

If a + b + c = p and ab + bc + ca = q; find a² + b² + c².

If x + y - z = 4 and x² + y² + z² = 30, then find the value of xy - yz - zx.