If logx/2 = logy/3, find the value of y^4/x^6.

Given, ⇒ 3log x = 2log y ⇒ log x 3 = log y 2 ⇒ x 3 = y 2 Squaring both sides we get, ⇒ x 6 = y 4 ⇒ . Hence, .