If log 27 = 1.431, find the value of : (i) log 9 (ii) log 300

Given, ⇒ log 27 = 1.431 ⇒ log 3 3 = 1.431 ⇒ 3 log 3 = 1.431 ⇒ log 3 = = 0.477 .......(1) (i) Solving, ⇒ log 9 ⇒ log 3 2 ⇒ 2 log 3 Substituting value of log 3 from equation (1) in above equation, we get : ⇒ 2 × 0.477 ⇒ 0.954 Hence, log 9 = 0.954 (ii) Solving, ⇒ log 300 ⇒ log 3 × 100 ⇒ log 3 + log 100 ⇒ 0.477 + log 10 2 ⇒ 0.477 + 2 log 10 ⇒ 0.477 + 2 × 1 ⇒ 0.477 + 2 ⇒ 2.477 Hence, log 300 = 2.477

If log y + 2 log x = 2, the value of y in terms of x is :
x² ÷ 100
100 ÷ x²
x ÷ 10
10 ÷ x

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If log₁₀ a = b, find 10^{3b - 2} in terms of a.

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If log₅ x = y, find 5^{2y + 3} in terms of x.

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Mathematics

If log 27 = 1.431, find the value of :
(i) log 9
(ii) log 300

Logarithms

Related Questions

If log y + 2 log x = 2, the value of y in terms of x is :
x² ÷ 100
100 ÷ x²
x ÷ 10
10 ÷ x

If log₁₀ a = b, find 10^{3b - 2} in terms of a.

If log₅ x = y, find 5^{2y + 3} in terms of x.

Mathematics

If log 27 = 1.431, find the value of :(i) log 9(ii) log 300

Logarithms

Related Questions

If log y + 2 log x = 2, the value of y in terms of x is :x2 ÷ 100100 ÷ x2x ÷ 1010 ÷ x

If log10 a = b, find 103b - 2 in terms of a.

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If log 27 = 1.431, find the value of :
(i) log 9
(ii) log 300

If log y + 2 log x = 2, the value of y in terms of x is :
x² ÷ 100
100 ÷ x²
x ÷ 10
10 ÷ x

If log₁₀ a = b, find 10^{3b - 2} in terms of a.

If log₅ x = y, find 5^{2y + 3} in terms of x.