KnowledgeBoat Logo
|

Mathematics

If log10 a = b, find 103b - 2 in terms of a.

Logarithms

30 Likes

Answer

Given,

⇒ log10 a = b

⇒ 10b = a

Cubing both sides, we get :

⇒ (10b)3 = a3

⇒ 103b = a3

Dividing both sides by 102, we get :

103b102=a3102103b2=a3100.\Rightarrow \dfrac{10^{3b}}{10^2} = \dfrac{a^3}{10^2} \\[1em] \Rightarrow 10^{3b - 2} = \dfrac{a^3}{100}.

Hence, 103b - 2 = a3100.\dfrac{a^3}{100}.

Answered By

16 Likes


Related Questions