If log₁₀ x = a and log₁₀ y = b, find the value of xy.

Given,

log₁₀x = a

⇒ x = 10^a.

log₁₀y = b

⇒ y = 10^b

xy = 10^a.10^b = 10^{a + b}.

Hence, xy = 10^{a + b}.