Prove that :

log₁₀ 125 = 3(1 - log₁₀ 2)

The value of (log 8 - log 2) ÷ log 32 is :

1. $\dfrac{2}{5}$

2. $\dfrac{5}{2}$

3. 2

4. 4

If 2 log x = log 250 - 1, the value of x is :

1. 17

2. -5

3. 5

4. 10

If log₃ x - log₃ 2 - 1 = 0; the value of x is :

1. 3

2. -3

3. -6

4. 6