The value of (log 8 - log 2) ÷ log 32 is :

1. $\dfrac{2}{5}$

2. $\dfrac{5}{2}$

3. 2

4. 4

Simplifying the expression :

$\Rightarrow \text{(log 8 - log 2) ÷ log 32} \\[1em] \Rightarrow \dfrac{\text{log 8 - log 2}}{\text{log 32}} \\[1em] \Rightarrow \dfrac{\text{log 2}^3 - \text{log 2}}{\text{log 2}^5} \\[1em] \Rightarrow \dfrac{\text{3 log 2 - log 2}}{\text{5 log 2}} \\[1em] \Rightarrow \dfrac{\text{2 log 2}}{\text{5 log 2}} \\[1em] \Rightarrow \dfrac{2}{5}.$

Hence, Option 1 is the correct option.