Mathematics
If the width of the uniform shaded portion is x m; its area in terms of x is :

320 m2 - (16 - 2x)(20 - 2x) m2
320 m2 - (16 - x)(20 - x) m2
320 m2 - (16 - 2x)(20 - x) m2
320 m2 - (16 - x)(20 - 2x) m2
Quadratic Equations
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Answer
From figure,

EF = 16 - x - x = (16 - 2x) meters
FG = 20 - x - x = (20 - 2x) meters
Area of shaded portion = Area of rectangle ABCD - Area of rectangle EFGH
= AB × BC - EF × FG
= 16 × 20 - (16 - 2x)(20 - 2x)
= 320 m2 - (16 - 2x)(20 - 2x) m2.
Hence, Option 1 is the correct option.
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