If x = 2 and y = 1 ; find the value of (-4x^2y^3) x (-5x^2y^5).

Question

KnowledgeBoat · Accepted Answer

(\-4x²y³) (\-5x²y⁵) = (-4) (-5)x⁽²⁺²⁾y⁽³⁺⁵⁾ = 20 x⁴y⁸ When x = 2 and y = 1, = 20 x 2⁴ x 1⁸ = 20 x 16 x 1 = 320 Hence, if x = 2 and y = 1 ; the value of (\-4x²y³) x (\-5x²y⁵) = 320.

Mathematics

If x = 2 and y = 1 ; find the value of (-4x²y³) x (-5x²y⁵).

Algebraic Expressions

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Mathematics

If x = 2 and y = 1 ; find the value of (-4x2y3) x (-5x2y5).