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Mathematics

If x = 2 and y = -3, find the values of

(i) xx + yy

(ii) xy + yx

Indices

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Answer

(i) xx + yy = 22 + (-3)-3

= 4 + (13)3\Big(-\dfrac{1}{3}\Big)^3

= 4 + 127-\dfrac{1}{27}

= 4 - 127\dfrac{1}{27}

= 108127=10727=32627\dfrac{108 - 1}{27} = \dfrac{107}{27} = 3\dfrac{26}{27}.

Hence, xx + yy = 326273\dfrac{26}{27}.

(ii) xy + yx

xy+yx=23+(3)2=(12)3+9=18+9=1+728=738=918.x^y + y^x = 2^{-3} + (-3)^{2} \\[1em] = \Big(\dfrac{1}{2}\Big)^3 + 9 \\[1em] = \dfrac{1}{8} + 9 \\[1em] = \dfrac{1 + 72}{8} \\[1em] = \dfrac{73}{8} = 9\dfrac{1}{8}.

Hence, xy + yx = 9189\dfrac{1}{8}.

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