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Mathematics

If x and y be unequal and x : y is the duplicate ratio of x + z and y + z, prove that z is mean proportional between x and y.

Ratio Proportion

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Answer

According to question,

xy=(x+z)2(y+z)2xy=x2+z2+2xzy2+z2+2yzx(y2+z2+2yz)=y(x2+z2+2xz)xy2+xz2+2xyz=yx2+yz2+2xyzxz2yz2=2xyz2xyz+yx2xy2z2(xy)=xy(xy)z2=xy.\Rightarrow \dfrac{x}{y} = \dfrac{(x + z)^2}{(y + z)^2} \\[1em] \Rightarrow \dfrac{x}{y} = \dfrac{x^2 + z^2 + 2xz}{y^2 + z^2 + 2yz} \\[1em] \Rightarrow x(y^2 + z^2 + 2yz) = y(x^2 + z^2 + 2xz) \\[1em] \Rightarrow xy^2 + xz^2 + 2xyz = yx^2 + yz^2 + 2xyz \\[1em] \Rightarrow xz^2 - yz^2 = 2xyz - 2xyz + yx^2- xy^2 \\[1em] \Rightarrow z^2(x - y) = xy(x - y) \\[1em] \Rightarrow z^2 = xy.

Since, z2 = xy hence, proved that z is mean proportional between x and y.

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