If x² - 4x - 5 = 0, values of x correct to two decimal places are :

1. 5.00 or -1.00

2. 5 or 1

3. 5.0 and -1.0

4. -5.00 and -1.00

Comparing equation x² - 4x - 5 = 0 with ax² + bx + c = 0, we get :

a = 1, b = -4 and c = -5.

By formula,

x = $\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Substituting values we get :

$x = \dfrac{-(-4) \pm \sqrt{(-4)^2 - 4 \times 1 \times -5}}{2 \times 1} \\[1em] = \dfrac{4 \pm \sqrt{16 + 20}}{2} \\[1em] = \dfrac{4 \pm \sqrt{36}}{2} \\[1em] = \dfrac{4 \pm 6}{2} \\[1em] = \dfrac{4 + 6}{2} \text{ or } \dfrac{4 - 6}{2} \\[1em] = \dfrac{10}{2} \text{ or } \dfrac{-2}{2} \\[1em] = 5.00 \text{ or } -1.00$

Hence, Option 1 is the correct option.