Mathematics

In an examination, the pass mark is 40%. If a candidate gets 65 marks and fails by 3 marks; find the maximum marks.

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Given:

Passing marks = 40%

Marks scored by candidate = 65 marks

Marks candidate fails by = 3 marks

Let $x$ be the maximum marks.

∴ Passing marks = $\dfrac{40}{100} \times x$

= $\dfrac{2}{5}\times x$

= $\dfrac{2x}{5}$ ……….(1)

Since, the candidate got 65 marks and fails by 3 marks. Hence, we can say that passing marks = (65 + 3) = 68 marks.

Using equation (1), we get,

⇒ $\dfrac{2}{5} \times x = 68$

⇒ $x = \dfrac{68 \times 5}{2}$

⇒ $x = \dfrac{340}{2}$

⇒ $x = 170$

The maximum marks = 170.

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