In an objective type paper of 150 questions, John got 80% correct answers and Mohan got 64% correct answers.

(i) How many correct answers did each get ?

(ii) What percent is Mohan's correct answers to John's correct answers ?

Given:

Total questions = 150

Percentage of correct answers for John = 80%

Percentage of correct answers for Mohan = 64%

(i) Number of correct answers John got = 80% of the total questions

= $\dfrac{80}{100} \times 150$

= $\dfrac{12000}{100}$

= $120$

Number of correct answers Mohan got = 64% of the total questions

= $\dfrac{64}{100} \times 150$

= $\dfrac{9600}{100}$

= $96$

John got 120 correct answers and Mohan got 96 correct answers.

(ii) Percentage = $\dfrac{\text{Mohan's correct answers}}{\text{John's correct answers}} \times 100$ %

= $\dfrac{96}{120} \times 100$ %

= $\dfrac{9600}{120}$ %

= $80$ %

Mohan's correct answers to John's correct are 80 %.