In parallelogram PQRS, ∠Q = (4x - 5)° and ∠S = (3x + 10)°. Calculate: ∠Q and ∠R.

It is given that in parallelogram PQRS, ∠Q = (4x - 5)° and ∠S = (3x + 10)°.

In a parallelogram, opposite angles are equal, so:

∠Q = ∠S and ∠R = ∠P.

Therefore,

⇒ (4x - 5)° = (3x + 10)°

⇒ 4x° - 5° = 3x° + 10°

⇒ 4x° - 3x° = 5° + 10°

⇒ 1x° = 15°

So, ∠Q = (4x - 5)°

= (4 $\times$ 15 - 5)°

= (60 - 5)°

= 55°

As we know, the consecutive angles of a parallelogram are supplementary.

⇒ ∠Q + ∠R = 180°

⇒ 55° + ∠R = 180°

⇒ ∠R = 180° - 55°

⇒ ∠R = 125°

Hence, ∠Q = 55° and ∠R = 125°.