Mathematics
In the adjoining diagram, ST is not parallel to PQ. The necessary and sufficient conditions for △ PQR ~ △ TSR is :
∠PQR = ∠STR
∠QPR = ∠TSR
∠PQR = ∠TSR
∠PRQ = ∠RST

Similarity
27 Likes
Answer
Given,
△ PQR ~ △ TSR.
From figure,
⇒ ∠PRQ = ∠SRT (Common angle)
The order of vertices of two similar triangles are written in such a way that the corresponding vertices occupy the same position.
∴ ∠PQR = ∠TSR
∴ △ PQR ~ △ TSR (By A.A. axiom)
Hence, Option 3 is the correct option.
Answered By
13 Likes
Related Questions
In the given diagram (not draw to scale), railway stations A, B, C, P and Q are connected by straight tracks. Track PQ is parallel to BC. The time taken by a train travelling at 90 km/hr to reach B from A by the shortest route is :
8 minutes
12 minutes
16.8 minutes
20 minutes

In the given diagram, △ ABC and △ DEF (not drawn to scale) are such that ∠C = ∠F and , then
△ ABC ~ △ DEF
△ BCA ~ △ DEF
△ CAB ~ △ DEF
the similarity of given triangles cannot be determined.

The scale factor of a picture and the actual height of Sonia is 20 cm : 1.6 m. If her height in the picture is 18 cm, then her actual height is :
14.4 m
2.25 m
1.78 m
1.44 m
In the adjoining figure, O is the center of the circle, and a semicircle is drawn on OA as the diameter. ∠APQ = 20°. The degree measure of ∠OAQ is :
25°
40°
50°
65°
