Mathematics
In the adjoining figure, two chords AB and CD of a circle intersect at P. If AB = CD, prove that arc AD = arc CB.
Related Questions
A and B are points on a circle with center O. C is a point on the circle such that OC bisects ∠AOB, prove that OC bisects the arc AB.
Prove that the angle subtended at the center of a circle is bisected by the radius passing through the mid-point of arc.
If P and Q are any two points on a circle, then the line segment PQ is called a
radius of the circle
diameter of the circle
chord of the circle
secant of the circle.
If P is a point in the interior of a circle with center O and radius r, then
OP = r
OP > r
OP ≥ r
OP < r