D is a point in side BC of triangle ABC. If AD > AC, show that AB > AC.

In the following figure, ∠BAC = 60° and ∠ABC = 65°. Prove that :

(i) CF > AF

(ii) DC > DF

From the following figure; prove that :

(i) AB > BD

(ii) AC > CD

(iii) AB + AC > BC

In a quadrilateral ABCD; prove that :

(i) AB + BC + CD > DA

(ii) AB + BC + CD + DA > 2AC

(iii) AB + BC + CD + DA > 2BD