In the given figure, a rectangular tin foil of size 22 cm by 16 cm is wrapped around to form a cylinder of height 16 cm. Find the volume of the cylinder.

From figure,

The cylinder formed will have,

height = 16 cm.

and circumference of cross section = 22 cm.

We know circumference = 2πr.

$\therefore 2πr = 22 \\[1em] \Rightarrow 2 \times \dfrac{22}{7} \times r = 22 \\[1em] \Rightarrow \dfrac{44}{7}r = 22 \\[1em] \Rightarrow r = \dfrac{22 \times 7}{44} \\[1em] \Rightarrow r = \dfrac{154}{44} \\[1em] \Rightarrow r = 3.5 \text{ cm.}$

Volume of cylinder = πr²h.

Putting values we get,

$\text{Volume of cylinder } = \dfrac{22}{7} \times (3.5)^2 \times 16 \\[1em] = \dfrac{22 \times 12.25 \times 16}{7} \\[1em] = \dfrac{4312}{7} \\[1em] = 616 \text{ cm}^3.$

Hence, the volume of cylinder = 616 cm³.