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Mathematics

If the inner curved surface of the well in part (i) above is to be plastered at the rate of ₹ 300 per m2, find the cost of plastering (around to the nearest hundred rupees).

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Answer

By formula,

Curved surface area of cylinder = 2πrh

Curved surface area of cylinder =2×227×1×20=8807m2\text{Curved surface area of cylinder }= 2 \times \dfrac{22}{7} \times 1 \times 20 \\[1em] = \dfrac{880}{7} m^2

Rate of plastering = ₹ 300/m2.

Cost of plastering = Curved surface area of cylinder x Rate

= 8807×300=2640007=37,714.28\dfrac{880}{7} \times 300 = \dfrac{264000}{7} = 37,714.28 \approx ₹ 37,700

Hence, the cost of plastering the inner curved surface area of the well = ₹ 37,700.

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