Mathematics
In the given figure, AD ⊥ BC and AB = AC, then :
△ ABD ≇ △ ACD
BD = CD
∠BAC = 90°
∠CAD = 45°

Triangles
19 Likes
Answer
We know that,
Angles opposite to equal sides are equal.
Since, AB = AC,
∴ ∠C = ∠B.
In △ ABD and △ ACD,
⇒ AB = AC (Given)
⇒ AD = AD (Common side)
⇒ ∠B = ∠C (Proved above)
∴ △ ABD ≅ △ ACD (By S.A.S. axiom)
We know that,
Corresponding sides of congruent triangles are equal.
∴ BD = CD.
Hence, Option 2 is the correct option.
Answered By
10 Likes
Related Questions
In the given figure, ∠B = ∠C and ∠BAD = ∠CAD, then :
AB = AC
AB ≠ AC
∠ADB ≠ ∠ADC
∠ADB ≠ 90°

In the given figure, AD = BD, then angle ACD is :
43°
22°
65°
28°

In the given figure; BE = DC, then :
AD = DC
AE = BE
AD = AE
∠ABE = ∠DAC

In △ ABC and △ PQR, AB = AC, ∠C = ∠P and ∠B = ∠Q; then triangles are :
isosceles but not congruent
isosceles and congruent
congruent but not isosceles
neither isosceles nor congruent.